Orthonormal basis. Linear Algebra. Hint.

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Let $\lbrace u_{1}, ..., u_{n} \rbrace$ an orthonormal basis of $\mathbb{R}^{n}$, then $\displaystyle x = \sum_{i=1}^{n}\langle x, u_{i} \rangle u_{i}$ for all $x \in \mathbb{R}^{n}$.

I know that $\langle u_{i}, u_{i} \rangle = 1$ and $\langle u_{i}, u_{j} \rangle = 0$ if $i \neq j$, but I don't know how to use this information in this question. I didn't want the solution, just a hint.

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Hint: Write $x=x_1u_1+\dots+x_nu_n$ and take its inner product with $u_i$.

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If $$x=\sum_{j=1}^na_ju_j$$ than, by linearity of the inner product, we have: $$ \langle x,u_i\rangle=\langle \sum_{j=1}^na_ju_j, u_i\rangle= \sum_{j=1}^na_j\langle u_j,u_i\rangle=\sum_{j=1}^na_j \delta_{i,j} = a_i $$