The surface area of a cylinder of height 2 units is $2\pi r^2 + 2\pi rh,$ which is greater than its volume $V = \pi r^2h=2\pi r^2$. Am I missing something? This is so weird!
2026-04-06 20:44:02.1775508242
Paradox of a unit 2 height cylinder
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There is no rule that the surface area must be less than the volume. They are totally different units.
Consider the unit cube with sides of length $1\, m$. The volume is $1 \, m^3$ but the surface area is $6 \, m^2$.
The same holds in two dimensions, a unit square with sides of length $1\, m$ has a perimeter of $4\,m$ and an area of $1\, m^2$.
To make things even more weird, there are objects with infinite surface area but finite volume, for example Gabriel's horn.