Partial Derivative

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$$f(x,y,z)=x^2+\ln(1+y)+e^{yz}$$

Why

$$f^\prime_y=\frac{1}{1+y}$$

and not

$$f^\prime_y=\frac{1}{1+y}+e^{yz}z$$

having in mind that the third addend in $f$ also contains $y$ (which is a real variable, not a constant)?

This is how I would do this:

$$f^\prime_y=0+\frac{1}{1+y}(1+y)\prime+e^{yz}(yz)\prime=\frac{1}{1+y}+e^{yz}(y\prime z+yz\prime)=\frac{1}{1+y}+e^{yz}z,\text{where }x,z=\text{constants}$$

What is it that I do not understand here?