If I have $u(x,t)=f(p(x,t))$ where f and p are functions.
What would the partials $du/dx$ and $du/dt$ be. I'd really appreciate the help thankk you.
If I have $u(x,t)=f(p(x,t))$ where f and p are functions.
What would the partials $du/dx$ and $du/dt$ be. I'd really appreciate the help thankk you.
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Just apply the chain rule: $$\frac{\partial u}{\partial x}(x,t)=f'(p(x,t))\frac{\partial p}{\partial x}(x,t).$$