Is there a way to compute the number of partitions such that each set in the partition has a cardinality lower or equal to two? If yes, is there also an efficient algorithm to compute these partitions?
2026-03-29 19:15:59.1774811759
Partitions of set with maximal cardinality
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Let us call "classes" the subsets of a given partition.
One can associate to any of these partitions in a unique way a symmetric boolean ((0-1) entries) matrix $P$ with $P_{i,j}=0$ everywhere excepted:
$P_{i,i}=1$ if $\{i\}$ is a "class" with one-element (singleton),
$P_{i,j}=P_{j,i}=1$ if $\{i,j\}$ is a "class" with two elements.
We can therefore reformulate the issue into counting the number of symmetric boolean matrices with sum of lines or columns equal to $1$, i.e., symmetric permutation matrices, i.e., as well permutation matrices $P$ such that $P^2=I$.
This is known as the OEIS A000085 with recurrence relationship:
$$a_n=a_{n-1}+(n-1)a_{n-2}$$
A reference here.
Edit: This approach provides a rather direct way to program all these partitions. Here is a Matlab program which does the job for any (reasonable) $n$ :
Output for $n=5$: