Path derivative

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Let $\vec y$ be a vector that represents the path of a particle through space. If we define $w$ as the length of the path, would it be correct to say that $\displaystyle \frac{d\vec y}{dw}$ evaluated at any point on the curve is equal to the unit vector tangent to the path at that point?

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Yes, that's right. If we parametrize the curve with respect to some parameter $t$, then $\frac{d\vec y}{dt}$ at any given point is a vector that is tangent to the curve at any given point, so $\frac{\frac{d\vec y}{dt}}{\|\frac{d\vec y}{dt}\|}$ is the unit tangent vector. But in the case when we're parametrizing the curve with respect to the arc length $w$, the unit tangent vector is just $\frac{d\vec y}{dw}$, because $\|\frac{d\vec y}{dw}\|=1$. (Try proving that.)

EDIT: I should mention that the usual notation used is $\vec r$ and $s$ instead of $\vec y$ and $w$.