I have the following map defined on the unit square $0\leq x,y \leq 1$: $$B(x,y)=\begin{cases}(2x,y/3) & 0\leq x< 1/2\\ \\(2x-1,(2+y)/3)& 1/2\leq x < 1 \end{cases}$$
How do I find two points in this unit square which form a period-2 orbit of $B$?
2026-03-30 15:29:19.1774884559
period-2 orbit for a discrete time dynamical system
167 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in DYNAMICAL-SYSTEMS
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