Would the magnitude of the combined individual magnitudes just be zero due to there inner products?
2026-03-26 02:52:28.1774493548
Perpendicular Magnitudes
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We have that $$||x+y||^2=$$ $$(x+y)\cdot(x+y)=$$ $$(x+y)\cdot x + (x+y) \cdot y=$$ $$x\cdot x+y \cdot x + x \cdot y + y \cdot y=$$ $$x \cdot x + 2(x \cdot y)+y\cdot y=...$$