Physics: Columbs Law Over a Distance

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I have a superposition of charges problem, and the following details are important to problem. I have a charge $q_1=6\ \mathrm{\mu C}$ located at the origin $(0,0)$, in a Cartesian coordinate system in which the metrics of the set are in meters. I have as well another charge at the point $(.03,0)$, and the charge has a value of $q_2 = 1.50 \ \mathrm{\mu C}$. Finally I have a charge stationed at the point $(.05,0)$, and the charge has a charge of $q_3 = -2.00 \ \mathrm{\mu C}$

My Attempt

My Question is How to find the net force acting on charge 1.

To attempt the problem I have done the following: \begin{align*} F_{net_{q_1}}&= F_{21}+F_{31} \\ F_{net_{q_1}} &= k \ \cdot \ 6.00 \mathrm{\mu C} \ \cdot[\frac{1.50 \mathrm{\mu C}}{(.03 \mathrm{m})^2}-\frac{2.00 \mathrm{\mu C}}{(.02 \mathrm{m})^2}] \\ F_{net_{q_1}} &= 46.7 \mathrm{N} \end{align*}

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The net force should be

\begin{align*} F_{net_{q_1}} &= k \ \cdot \ 6.00 \mathrm{\mu C} \ \cdot[\frac{1.50 \mathrm{\mu C}}{(.03 \mathrm{m})^2}-\frac{2.00 \mathrm{\mu C}}{(.05 \mathrm{m})^2}] \end{align*}

Use 0.05 instead of 0.02 for the second distance.