.Find the plane equation that contains the X axis and the point A(4,-3,-1) The correct answer is y-3z=0 Anyone could explain me why is that the answer and is not -3y-1z=0? Thanks you in advanced! Sorry for my English, I'm Spanish
2026-03-29 16:54:28.1774803268
Plane equation exercise
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1
It will suffice to find two linearly independent points in the plane. One such point is the unit vector in the $x$-direction. That would be $(1,0,0)$. Another is the point $(4,-3,-1)$. Go ahead and take their cross-product to produce a vector normal to the plane. You know that each vector in this plane is then orthogonal to the normal vector. Can you get the equation for the plane from that?