Please clarify: Dimension of Direct Sums

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If $U_{1}\oplus...\oplus U_{m}=U_{1}+...+U_{m}$ implies that $U_{1}\cap...\cap U_{m}=\{0\}$, how is it that we can say that dim $(U_{1}+...+U_{m})=$ dim $U_{1}+...+$ dim $U_{m}$?

Wouldn't this go against the the true statement dim $(U_{1}+...+U_{m})=$ dim $U_{1}+...+$ dim $U_{m} -$ dim $U_{1}\cap...\cap U_{m}$?

Unless dim $\{0\}$ is zero?

Is the dimension of a set containing only the zero vector equal to zero? I don't see that in my book.