Consider this:
Ginny opens a savings account and decides to pay £200 into the account at the start of each month. At the end of each month, interest of 0.5% is paid into the account. Show that the total interest paid into the account over the first 12 months is £79.45 to the nearest penny.
Model 1 of solving used by the mark scheme:
- After one month, the interest paid is 0.5% of £200, or £1.
- After two months, the interest paid is 0.5% of £200 for the first month plus 0.5% of (£200 + £1) for the second month, or £1 + £1.005 = £2.005.
- After three months, the interest paid is 0.5% of £200 for the first month plus 0.5% of (£200 + £1) for the second month plus 0.5% of (£200 + £1 + £2.005) for the third month, or £1 + £1.005 + £1.010025 = £3.015025.
This forms a sequence: 1, 1.0025, 1.0050125 with first term 1, and common ratio 1.005. From here the sum of the first 12 months can be calculated easily.
Alternative model 2 which makes more logical sense to myself:
- Start of month 1= 200, end of month 1 = 200*1.005 = 201
- Start of month 2=201+200=401, end of month 2 = 401*1.005=403.005
- Start of month 3 = 403.005+200=603.005, end of month 3 = 603.005*1.005=606.020025.
Thus at the end of month 1, £1 is paid interest; end of month 2, £2.005 is paid interest; end month 3, £3.015025 is paid interest
Please can somebody explain the discrepancy behind this. If the model 1 (using geometric sequence) is correct then how would one derive this?
Thanks.
Model 1 should be:
So you get something like this for the interest using the Model 1 approach. You can also see the £606.020025 from model 2 (if you ignore the £600).