$|\sinh x|\geq|x|, \forall x \in \mathbb{R}$
$$ f(x) = \sinh x $$
$$f'(c)= \frac{f(b)-f(a)}{b-a} $$
$$\cosh (c)= \frac{\sinh b-\sinh a}{b-a} $$
what can I do this continuous?
$|\sinh x|\geq|x|, \forall x \in \mathbb{R}$
$$ f(x) = \sinh x $$
$$f'(c)= \frac{f(b)-f(a)}{b-a} $$
$$\cosh (c)= \frac{\sinh b-\sinh a}{b-a} $$
what can I do this continuous?
From $$\cosh c=\frac{\sinh b-\sinh a}{b-a}$$
Let $b=x$ and $a=0$, then we have $$\cosh c=\frac{\sinh x-\sinh 0}{x-0}$$
That is $$|\frac{\sinh x}{x}| = |\cosh c| \ge 1$$
Cross multiply to get $$|\sinh x|\ge |x|$$