Points of discontinuity of composition of continuous and discontinuous functions

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Suppose that $f:[a,b]\rightarrow\mathbb{R}$ has countably many discontinuous points and $g:\mathbb{R}\rightarrow (-\pi/2,\pi/2)$ is a countinous function ($g=\arctan$). What to say about the points of discontinuity of $g\circ f=\arctan(f)$?

My thoughts are that there are at most as many points of discontinuity as $f$ has. Is it true?

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If $f$ is continuous at $a$ and $g$ is continuous at $f(a)$, then $g\circ f$ is continuous at $a$.

Since your $g$ is continuous everywhere, it follows that $g \circ f$ is continuous at every point where $f$ is continuous. Said another way, if $g \circ f $ is discontinuous at $a$, then so is $f$. So yes, your conclusion is correct.