$f_n(x) = \frac{n^2x}{1+n^3x^2}$
I claim the above function is continuous.
For $[a, ∞) , a>0$
I have tried and found out that it is pointwise convergent.
For uniform convergence, I found out that $| f_n(x) - f(x)| < \frac{1}{n^4a^3} < \epsilon$ so it is uniform convergent, but I heard that uniform convergence is only on a close interval?
Uniform convergence is not only (and not always) on closed intervals.
The interval $[a,+\infty)$ is actually closed.