I dont really know how to go about this question. I know that the area is
$$\int_\alpha^\beta \frac12 r^2\, d\theta $$
The question is to find the area of the shaded region.

I dont really know how to go about this question. I know that the area is
$$\int_\alpha^\beta \frac12 r^2\, d\theta $$
The question is to find the area of the shaded region.

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If you read through the links I left on the comments, you should see that the area that's trapped between two polar curves should be:
$$\int_{\alpha}^\beta \frac12 r^2_{out} d\theta - \int_{\alpha}^\beta \frac12 r^2_{in} d\theta$$
Or more compactly,
$$\frac12 \int_{\alpha}^\beta (r^2_{out} - r^2_{in}) d\theta.$$
Note: This formula should remind you of the formula you learned for finding area between two functions.
$r_{out}$ corresponds to the curve that is further out, further away from the origin. (Remember $r$ represents the distance from the origin.)
$r_{in}$ represents the curve that is closer to the origin, closer to the origin.
$\alpha$ and $\beta$ represent the angle (in polar coordinates) of the intersection points of the two curves. To find $\alpha$ and $\beta$, you need to set the two curves in question and solve for $\theta$.
Let me know if you need more help. I can update this post with more details if needed.