Evaluate $\int(x^2+y^2)^{1/2}dA$ where $D$ is region enclosed by the two circles: $x^2+y^2=64$ and $x^2+(y-4)^2=16$.
I'm confused on what the limits of integration for the corresponding double integral will be once converted to polar coordinates?
2026-04-07 11:11:18.1775560278
Polar Coordinates Double Integral Question
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You're integrating the region between two circles, one with centre at the origin and radius 8, one with centre at $(0,4)$ and radius 4. To solve the problem, find the angles of the points where the circles intersect to get the limits of integration for $\theta$ and use the equations of the circles as your upper and lower limits of integration for the radius.