Polarform Solution e function

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Just a very small question just to make sure:

I should solve for $$(e^{-i\frac{\pi}{2}})^{20}$$and I get the solution that $$e^{–\pi}=-1$$ since $cos(\pi)=-1$. However, the sample solution says it’s positive 1.

Could someone explain?

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$(e^{i\frac{\pi}{2}})^{20}=e^{i 10\pi}=1.$