I need help with this task. I have to prove that $$\int_{\gamma} P(z)dz =0$$ for every polynomial $P$ and every closed path $\gamma$ in $\mathbb C$.
2026-03-25 06:09:02.1774418942
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Polynomial and closed path
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IF $\gamma$ IS PIECEWISE SMOOTH:
Then since $\gamma$ is closed, and polynomials are entire and have primitives (which are also polynomials), we can conclude from either
Cauchy's Integral Theorem
The complex analogue of the fundamental theorem of calculus.
OTHERWISE:
Then I can understand why you would need help.
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IF $\gamma$ IS PIECEWISE SMOOTH:
$\left(\dfrac{1}{n+1}a_{n}z^{n+1}+\cdots+\dfrac{1}{2}a_{1}z^{2}+a_{0}z\right)'=a_{n}z^{n}+\cdots+a_{1}z+a_{0}:=P(z)$, so the integral is just the difference of the endpoints of $y$ taken by the primitive.