Polynomials and Jordan form

166 Views Asked by At

Problem Let A ($n\times n$ matrix) be a single Jordan block and let $C$ be an $n\times n$ matrix that commutes with $A$. Prove that $C = f(A)$ for some polynomial $f$.

1

There are 1 best solutions below

0
On BEST ANSWER

One way to do this is to

  • first, using the fact that $A$ has one jordan block, compute the dimension of the space of all matrices of the form $f(A)$;

  • second, compute explicitely the space of matrices which commute with $A$, and determine its dimension

  • observe that the first subspace is contained in the second one, and look at their dimensions.