Assume $G$ is a Lorentzian matrix, which means it has signature $(+,-,\cdots,-)$, and $v$ is a unit timelike vector, i.e. $v^TGv=1$.
So do we have that matrix $2Gvv^TG-G$ is positive definite?
Any advice is helpful. Thank you.
Assume $G$ is a Lorentzian matrix, which means it has signature $(+,-,\cdots,-)$, and $v$ is a unit timelike vector, i.e. $v^TGv=1$.
So do we have that matrix $2Gvv^TG-G$ is positive definite?
Any advice is helpful. Thank you.
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