I am wondering,
I have 4 QB's, 8 RB's, 12 WR's, 4 TE's, 4 K's, 4 Def,
I can only play 1 QB, 2 RB's, 3 WR's, 1 TE, 1 K, 1 DEF
for a total of nine players.
How many different combinations do I have?
Thanks!
Thane
I am wondering,
I have 4 QB's, 8 RB's, 12 WR's, 4 TE's, 4 K's, 4 Def,
I can only play 1 QB, 2 RB's, 3 WR's, 1 TE, 1 K, 1 DEF
for a total of nine players.
How many different combinations do I have?
Thanks!
Thane
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Hint: There are $\binom{4}{1}$ ways to choose the QB. For each such way, there are $\binom{8}{2}$ ways to choose the RB's. For every way of choosing the QB and the RB's, there are $\binom{12}{3}$ ways to choose the WR's. And so on.