Possible number of arrangement.

Question

Question:

How many cars are there with number GJ-X-AB-abcd. GJ and A are constant.X is digit between 1 to 9, B is english alphabet and abcd is 4 digit number.(a can be zero)

My Efforts:

It is but natural car's number plate have repetition.

So, X can be arranged in 9 different ways.

AB can be arranged in 26 different ways.

abcd can be arranged in $10\times10\times10\times10=10000$ different ways.

So the total number of arrangement is $2340000$. But answer given is $2339766$, which is a little less than the expected.

Answer 1

abcd can be arranged in $10 \times 10 \times 10 \times 10=10000$ different ways, but it also contain 0000, which need to be excluded from total arrangement.

0000 can come $26 \times 9= 234$ times in arrangement.

Therefore, $234$ is to be subtracted from total possible arrangement.

$2340000-234=23393766$

Thank you Gerry Myerson for your help.