In my Operations Management course, we are given a set of nodes in a graph $\{A,B,C,D,E,F,G,H,I\}$, and are given a set of predecessor nodes, i.e., nodes that immediately come before the given node in the graph as $\{NULL, A, A, B, C, (D,E), (D,E), F, G\}$. I.e., nothing immediately precedes A, but A immediately comes before B, and D and E come immediately before F.
My question is: Without drawing a graph, is it possible to figure out the paths that connect node $A$ to node $I$? We are told that there are 4 such paths.
Thanks!
My strategy was working backwards. I must be preceded by G, G can be preceded by either D or E, so you need two possible cases. At this point my tableau looks like $$\frac{D}{E}GI$$ Then D can only be preceeded by B which can only be preceeded by A, and E can only be preceeded by C which can only be preceeded by A. Since we got to the root in all of our cases, we are done. The tableau looks like$$\frac{ABD}{ACE}GI$$
So we read off from that that the two possible paths are ABDGI and ACEGI,