Primitive $r/(1+r^2)$ without abs()

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Why should there not be an absolute value-sign instead of () when I find the primitive of $r/(1+r^2)$? Maybe it should only be there when I derive?

http://www.wolframalpha.com/input/?i=primitive+r%2F%281%2Br%5E2%29

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In principle there shoud be, but since r2+1>0, for all r∈ℝ, you can remove them. In any case, if I recall correctly, WA never includes abs even when it's necessary. -- Git Gud Apr 16 at 10:54