$L$ is the side of a square, and it is 10cm.
In the exercise I have a square shape which is cut with a semicircle in the bottom, and the radius of the semicircle is half the side of the square.
I need steps to prove that
$\displaystyle\frac{\pi L^2}{8} = \frac{\pi r^2}{2}$ (semicircle)
I eventually come to the place where both equations stay equal, 1/8 * Phi * L ² = 1/8 * Phi * L ², but Id like to know which steps I need to make the equation something like 1 = 1, so there's nothing more to do.
Thanks a lot.
Note that, $\displaystyle r=\frac{L}{2}$ then replacement $r$, in $\displaystyle\frac{\pi r^2}{2}$ you obtain $\displaystyle\frac{\pi L^2}{8}$
Know that, the semicircle area is $\displaystyle\frac{\pi r^2}{2}$ how $\displaystyle r=\frac{L}{2}$ then:
$$\frac{\pi r^2}{2}=\frac{\pi (L/2)^2}{2}=\frac{\pi (L)^2}{4\cdot2}=\frac{\pi (L)^2}{8}$$
and is solved.