I'm solving a solid of revolution problem and I'm stuck at this point. The u-subtitution doesn´t work, I don´t know what method use.
$\pi\int(\frac{4x-1}{8x^4})^2$
2026-04-02 21:21:34.1775164894
Problem in solving an Integral.
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This is the way that Andre suggest in the comment and the straightforward way:$(4x-1)^2=16x^2-8x+1$, then $ (4x-1)^2/(64x^8)=1/4x^6-1/8x^7+1/64x^8$