I have the following Differential equation which I need to solve:
$$\frac{\mathrm{d^2} y}{\mathrm{d} x^2} = \left(\frac{\mathrm{d} y}{\mathrm{d} x}\right)^2$$
I know how to solve a second order linear differential equations but this is something strange equation which I have seen before while practicing the Differential equation Chapter. Please tell me how to go about solving this Differential equation problem. Any intial hint would do for me.
Thanks
Put $\frac{dy}{dx}$ = $v$, after differentiating w.r.to $x$ you get $\frac{dv}{dx}$ = $v^2$
then $\frac{-1}{v}$ = $x+C$
or, $v$ = $\frac{-1}{x+C}$
so $\frac{dy}{dx}$ = $\frac{-1}{x+C}$
$y$ = $-ln(x+C)$ + K