Problem with calculation of the norm of a vector

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It is known that $\vec{u} [3,4]$ and $\vec{v}[2,k]$. And I need to find k such that the norm of the projection of ⃗ over ⃗ equals to 1.

I am trying to obtain the norm of the vector $\frac{6+4k}{25} \vec{u}$.

However, the answer key tells me that the norm would be $\frac{|6+4k|}{5}$

But I am not sure what to do in order to obtain such an answer?

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$$\Big\| \frac{6+4k}{25} u\Big\| = \frac{|6+4k|}{25}\|u\| = \frac{|6+4k|}{25}\sqrt{3^2+4^2} = \frac{|6+4k|}{5}$$