Is $1= -1$ ?
because, $1=\sqrt{1}
=\sqrt{-1×-1}
=\sqrt{-1}×\sqrt{-1 }
= i×i
= i^2 = -1 $
this can be done with all natural numbers. how this can be? please help me
2026-03-28 03:51:40.1774669900
problem with solving one complex number problem
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1
On complex number this step is wrong
$$1=\sqrt{1}$$
since $\sqrt{1}=(e^{2\pi i})^{\frac12}\pm 1$ and also this one
$$\sqrt{-1}=i$$
since $\sqrt{-1}=(e^{\pi i})^{\frac12}=\pm i$.