From WiKi: Product of exponentials formula is:
$$g_{st}=e^{\hat{\xi}_1\theta_1}e^{\hat{\xi}_2\theta_2}...e^{\hat{\xi}_n\theta_n}$$
where $g_{st}\in SE(3)$,and $\xi_i$ is twist vector $\in {se}(3)$.
My question is: for programming convenient, can i use
$$g_{st}=e^{\hat{\xi}_1\theta_1+\hat{\xi}_2\theta_2+...+\hat{\xi}_n\theta_n}$$
to avoid the matrix product. If cannot, why?
I think the answer is yes, because $\hat{\xi}_1\theta_1+...+\hat{\xi}_n\theta_n$ is still in Lie algebra $se(3)$. But what is its physical explanation?
The answer is NO, follows user10354138 comment, $\xi_j$ doesn't commute.