Given the set $\mathbb{C}^*\times \mathbb{C}$ with the group structure given by $(x,y)\cdot (z,w) =(xz, zy+wx) $. How can I check that this is reductive or not? ?
I think that its maximal normal solvable subgroup is itself, how can I see the identity component of this group?
Thanks
Two definitions and a property :
A linear representation $\rho:G\rightarrow GL(n,\mathbb{C})$ is completely reducible if for all $G$-invariant subspace $V$ in $\mathbb{C}^n$, there exists a $G$-invariant subspace $W$ for which $\mathbb{C}^n=V\oplus W$.
A group $G$ is linearly reductive if for all $n\geq 1$ and all group morphism $\rho:G\rightarrow GL(n,\mathbb{C})$ the linear representation $\rho$ is completely reducible.
Over a field of characteristic $0$, $G$ is linearly reductive if and only if its identity component $G^0$ is connected.
Remark that :
$G:=\mathbb{C}^*\times \mathbb{C}$ is connected because $\mathbb{C}^*$ and $\mathbb{C}$ are connected.
Regarding the property given above, and remark 1, in order to show that $G:=\mathbb{C}^*\times \mathbb{C}$ is not reductive, it suffices to find a representation $\rho_0:G\rightarrow GL(n,\mathbb{C})$ such that $\rho_0$ is not completely reducible.
Sketch of solution :