I can't find the proof of this corollary: if $R$ is a PID, then every finitely generated projective $R$-module is free.
Please help me.
2026-04-22 19:21:54.1776885714
Projective modules over PID
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A finitely generated projective $R$-module is a direct summand of a finitely generated free module. Furthermore, a submodule of a finitely generated free module over a P.I.D. is free.