Proof about $\Delta u = 0$ for poisson's formula for half-space

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I have questions about the proof of Theorem $14$ (poisson's formula for half-space) in Page $38$.

we easily verify as well $u \in C^\infty (\mathbb{R_+^n})$, with $$\Delta u(x) = \int_{\partial\mathbb{R_+^n}}\Delta_x K(x,y) g(y) dy = 0$$

I look up the post. I understand why $\Delta u(x) = \int_{\partial\mathbb{R_+^n}}\Delta_x K(x,y) g(y) dy$. The only thing confuses me is that $ \int_{\partial\mathbb{R_+^n}}\Delta_x K(x,y) g(y) dy = 0.$

So how can I prove that $ \int_{\partial\mathbb{R_+^n}}\Delta_x K(x,y) g(y) dy = 0$ then.

My question is why $ \int_{\partial\mathbb{R_+^n}}\Delta_x K(x,y) g(y) dy = 0$.