All matrices can be decomposed into the sum of a hermitian and an anti hermitian matrix
All hermitian and anti hermitian are diagonalisable
Sum of diagonal matrices is also a diagonal matrix
All matrices are diagonalisable.
Where does this "proof" go wrong????
It goes wrong because statement 4 doesn't follow from statements 1, 2, and 3. As PhoemueX pointed out in the comments, there is a difference between diagonal and diagonalizable. All diagonal matrices are diagonalizable, but not every diagonalizable matrix is diagonal.
While statements 1 and 2 correctly show that any matrix can be written as the sum of two diagonalizable matrices, statement 3 does not allow us to conclude that this sum is also diagonalizable.
In order to use statements 1, 2, and 3 to conclude statement 4, statement 3 would need to be "the sum of two diagonalizable matrices is also diagonalizable". But of course, this isn't true.
For example $\begin{bmatrix}1 & 0 \\ 0 & 0\end{bmatrix}$ is diagonal (and thus diagonalizable) and $\begin{bmatrix}0 & 1 \\ 0 & 1\end{bmatrix} = \begin{bmatrix}1 & 1 \\ 1 & 0\end{bmatrix}\begin{bmatrix}0 & 1 \\ 0 & 1\end{bmatrix}\begin{bmatrix}1 & 1 \\ 1 & 0\end{bmatrix}^{-1}$ is diagonalizable, but their sum $\begin{bmatrix}1 & 0 \\ 0 & 0\end{bmatrix}+\begin{bmatrix}0 & 1 \\ 0 & 1\end{bmatrix} = \begin{bmatrix}1 & 1 \\ 0 & 1\end{bmatrix} $ is not diagonalizable.