In the proof of analytic prime number theorem
how can i justify
$\int_{m}^{m+1} \sum_{n \leq x} \Lambda (n) dx = \sum_{n \leq m} \Lambda (n)$
where $\Lambda$ is Mangoldt function
In the proof of analytic prime number theorem
how can i justify
$\int_{m}^{m+1} \sum_{n \leq x} \Lambda (n) dx = \sum_{n \leq m} \Lambda (n)$
where $\Lambda$ is Mangoldt function
$\sum_{n \leq x} \Lambda (n)$ is constant on any interval not containing an integer, and its value on the interval $(m,m+1)$ equals $\sum_{n \leq m} \Lambda (n)$.