Prove that $\forall a,b,c,d$ E Z, if $a | c$ and $b | d$ then $(a+b) | (c+d)$
I've got up to here
$$c=ax$$ $$d=by$$ So $$c+d = ax+by$$
I believe that this a false statement but I don’t know where to go from here
Prove that $\forall a,b,c,d$ E Z, if $a | c$ and $b | d$ then $(a+b) | (c+d)$
I've got up to here
$$c=ax$$ $$d=by$$ So $$c+d = ax+by$$
I believe that this a false statement but I don’t know where to go from here
Copyright © 2021 JogjaFile Inc.