proof fibonacci sequence is small o(2^n) without using closed formula

274 Views Asked by At

I need to prove that for the given fibonacci sequence, with initial values:

f(1)=1

f(2)=2

f(n)=f(n-1)+f(n-2)

f(n) is belong to small o(2^n). I need to prove it without using the closed formula of fibonacci, or without proving it with generating functions etc.

I need a proof by induction/tree/iterations or something like that.

I proved that it's O(2^n), but can't prove for small o. I'll appreciated any help.