$s_{2^k}= 1+ \sum_{j=1}^{k}(\sum_{m=2^{k-1}+1}^{2^k} \frac 1m)$ How is this true? For example, when $2^k = 4$, $s_4 = 1+(1/3 +1/4)+(1/3+1/4)$, which is wrong.
Thank you in advance.
$s_{2^k}= 1+ \sum_{j=1}^{k}(\sum_{m=2^{k-1}+1}^{2^k} \frac 1m)$ How is this true? For example, when $2^k = 4$, $s_4 = 1+(1/3 +1/4)+(1/3+1/4)$, which is wrong.
Thank you in advance.
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This is obviously confusing.$$s_{2^k}= 1+ \sum_{j=1}^{k}(\sum_{m=2^{k-1}+1}^{2^k} \frac 1m)$$
It should have been $$s_{2^k}= 1+ \sum_{j=1}^{k}(\sum_{m=2^{j-1}+1}^{2^j} \frac 1m)$$
The proof is much easier to read without all this sigma stuff.