I came across an assumption made in the course of a derivation. The assumption states:
If $a,b,c,p,q \in Z$, then $|ap^2 + bpq + cq^2| \geq 1$
However, I feel that we can find values of $a,b,c,p,q \in Z \ni ap^2 + bpq + cq^2 = 0$, which violates the above assumption.
Please note that I attempted a few hit and trials and have not been able to find such set of values for $a,b,c,p,q$.
Can you please help validate or refute my understanding.
NOTE: Post @Julienne's help, it's important for me to add that the above needs to be seen in the context of the problem statement and not in isolation. The problem statement is as follows:
If $a,b,c \in Z$ and $ax2+bx+c=0$ has an irrational root, then prove than $|f(\lambda)| \geq \frac{1}{q^2}$ , where $\lambda \in (\lambda = \frac pq;p,q \in Z)$ and $f(x)=ax^2+bx+c$.
It suffices to take $p=0$. This reduces the original problem to $|cq^2| \geq 1$. By assumption, $c$ and $q$ are both integers, and $q$ is nonzero. Hence, $|cq^2|$ is atleast 1 provided that $c$ is not zero. Now, $c$ is in fact never zero because the discriminant is not a perfect square.