Proof of Lemma 6.1, II in Hartshorne

213 Views Asked by At

In Hartshorne's proof for Lemma 6.1, II, he said "it would be sufficient to show that there only finitely many prime divisors $Y$ of $U$ for which $v_Y(f) \neq 0$". How can we conclude that $v_Y(f) \neq 0$ for $Y$ is a prime divisor in $X$ if and only if $v_{Y'}(f) \neq 0$, with $Y' = Y \cap U$ ?