Prove {5^(6n+2) : n ∈ Z} ⊆ {125^m/5 : m ∈ Z}
I have worked out doesn't look correct?
I have done it by taking 125^m/5 -> 5^(6n+2)/5
Prove {5^(6n+2) : n ∈ Z} ⊆ {125^m/5 : m ∈ Z}
I have worked out doesn't look correct?
I have done it by taking 125^m/5 -> 5^(6n+2)/5
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Hint:
$$5^{6n+2}=5^{6n+3-1}=\frac{5^{3(2n+1)}}{5}$$