Proof of the construction of Dirac Delta

275 Views Asked by At

The Dirac Delta function pops up in a wide variety of applications, especially in applications that require Laplace and Fourier transforms.

But my question is: what's the proof that the distribution can be constructed in the first place? How can we determine that there exists a function that is zero at all points but one, this exception is at infinity, and that the integration of this distribution across its entire domain is one?

4

There are 4 best solutions below

0
On BEST ANSWER

The Dirac delta is the distribution defined by $$ \langle \delta_{x_0},\varphi \rangle = \varphi(x_0) $$ for all $\varphi \in \mathcal{D}(\mathbb{R}^n)$. It is not a function, so your question cannot be answered.

0
On

But my question is: what's the proof that the distribution can be constructed in the first place? How can we determine that there exists a function that is zero at all points but one, this exception is at infinity, and that the integration of this distribution across its entire domain is one?

Strictly only the last claim holds. $\langle f, \delta\rangle = \int f(x) \delta(x) \, dx = f(x_0)$.

1
On

There is no such "function". But in mathematics we use a construction in functional analysis. The "functional" $F$ defined by $F(g) = g(0)$ for all continuous $g$ is the one called "Dirac delta". In physics, they "pretend" there is an actual function, and do computations with it. Since it often produces useful results, there is little reason to stop doing that.

0
On

You can find an elementary treatment in Lighthill's book on Generalised Functions.

http://www.amazon.com/gp/aw/d/0521091284/ref=mp_s_a_1_1?qid=1432930439&sr=8-1&pi=SL75_QL70&keywords=Generalised+functions