Again I am stuck at some proof. I need to proof or deproof that for all linear equivalences:
So far I think it is correct because we get symmetry and linearity, but I have troubles to proof it. Any help is upvoted immediately.
here the def of linearity:
symmetry here:
transitiv:
reflexiv:
linear equivalent is: transitiv, reflexiv, symmetric and linear






It seem to be true.
You use symmetry and linearity according to the second formulations. Since $R$ is symmetric you have $R^{-1}\subseteq R$ and therefore $R = R^{-1}\cup R$ which by linearity will be equal to $\nabla_{X,X}$