The amount of 190 proof required to make 500 ml of 70% alcohol is?
The answer is 368 ml. Just couldn't figure how to get to that answer. Help me out, aye?
The amount of 190 proof required to make 500 ml of 70% alcohol is?
The answer is 368 ml. Just couldn't figure how to get to that answer. Help me out, aye?
On
So apparently we are mixing a strong alcohol ($190/2 = 95\%$) and water ($0\%$ alcohol) and we want a total of $0.5$ l of this mixture, and we want it to contain $70~\%$ alcohol. Let's assume that these are volume percentages. May the amount of alcohol be $A$. Then the amount of alcohol in the final product is $0.95A$, which should, on the other hand, be equal to $0.7 \times 0.5$. Therefore, $A=\frac{0.7 \times 0.5}{0.95}\approx 0.3684$.
$500$ ml of 70% alcohol has $0.7 \times 500 = 350$ ml of alcohol in it. $190$ proof hooch is $95$% alcohol. If $x$ is the number of ml needed, then $95$% of $x$ had better be $350$. That is $0.95 x = 350$, so $x= 350/0.95 = 368.42...$