Proof that a set is open.

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Let $(\Lambda_i)_{i\in I}$ a collection of linear operators from $X$ (Banach space) to $Y$ (Normed space).

Let $\alpha : X \rightarrow [0,\infty]$ be the function $\alpha(x):=\sup_{i \in I} \|\Lambda_ix\|$.

Let $A_n:=\{x \in X : \alpha(x)>n\}$

I want to prove in a direct way that this set is open for every $n\in \mathbb{N}$.

So I want to find an $r_{x_0}$ such that if $x_0 \in A_n$ then $\sup_{i \in I}\|\Lambda x\|>n$ for each $x$ in the open ball $B_{r_{x_0}}:=\{x\in X: \|x-x_0\|<r_{x_0}\}$ .

But I'm blocked. Can you give me a little help? Thank you!