Using the laws of sets, prove:
a. $ A - (B ∩ C) = (A ∩ B^{c}) $ $∪ $ $(A∩C^{c})$
b. $ (A -B)^{c} $ × C $= (A^{c} $ × $C) $ $∪ $ $(B $ × C$)$
My answers:
a. $ A - (B ∩ C) $ =
$ A∩(B ∩ C)^{c} $
$ A∩(B^{c} ∪ C)^{c} $ (De Morgan's Law)
$ (A∩B^{c}) ∪ (A ∩C^{c})$ (Distribution Law)
b. $ (A -B)^{c} $ × C =
$ (A × C ) \cup ( B $ × $ C )$
Have I correctly solved question a?
I am stuck on question b, as I am unsure how to correctly apply the laws of sets.
Part $a$ is correct.
For part $b$, note that \begin{align} (A-B)^c = (A \cap B^c)=A^c \cup B \end{align}