Why is this relation transitive? $R = \{(x,y)\in\Bbb N^2\mid x + 4y = 10\}$
2026-03-25 19:01:07.1774465267
Properties of equality
448 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail At
1
Assume x + 4y = 10 and y + 4z = 10. Does x + 4z = 10?
Exercise. Prove for x,y in N, x + 4y = 10, the solutions are
(2,2), (6,1).
Thus if aRb and bRc, then b = 2.
Whence a = b = c = 2, so aRc.