Properties of Variance for Random Variables

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Random Variables $X$ and $Y$ are independent. If $Var(X) = 4$ and $Var(Y) = 9$. Find $Var(2X-3Y-1)$

So this is what I did but it seems to be incorrect.

$Var(2X-3Y-1)$

$=Var(2X)-Var(3Y-1)$

$=2^2Var(X)-3^2Var(Y)$

$=4(4)-9(9)$

$=16-81$

$=-65$

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Variances always add, so the answer should be $16+81=97$.