Need help this question
Random Variables $X$ and $Y$ are independent. If $Var(X) = 4$ and $Var(Y) = 9$. Find $Var(2X-3Y-1)$
So this is what I did but it seems to be incorrect.
$Var(2X-3Y-1)$
$=Var(2X)-Var(3Y-1)$
$=2^2Var(X)-3^2Var(Y)$
$=4(4)-9(9)$
$=16-81$
$=-65$
Variances always add, so the answer should be $16+81=97$.