Property of big O notation multiplication

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In this document here: https://faculty.math.illinois.edu/~hildebr/595ama/ama-ch2.pdf on page 15, there is a property about pulling out factors for big O notation. Specifically, if $f(x) = O(g(x)h(x))$ then $f(x) = g(x)O(h(x))$. Is the converse true as well? That is if $f(x) = g(x)O(h(x))$ then $f(x) = O(g(x)h(x))$?

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O(H(x)) = any function G(x) with |$\frac{G(x)}{H(x)}$| $\leqslant$ M (that is ,bounded by a real number M over some range of the variable "x") . So yes ,Your two equality's are equivalent since dividing f by gh is the same as dividing f over g by h.